A.10
B.15
C.26
D.27
第4题
B.10,36
C.9,45
D.9,36
第6题
B.1234567890
C.0123456789
D.Notice提示信息
第7题
/*simple ping program*/
struct sockaddr_in saddr;
int rawsock;
unsigned short in_cksum(unsigned short*addr, int len)
{ int sum=0;
unsigned short res=0;
while(1en>1){
sum+=*addr++; len-=2;
}
if(len=1){
*((unsigned char *)(&res))=*((unsigned char *)addr); sum+=res;
}
sum=(sum>>16)+(sam & 0xffff);
sum+=(sum>>16); res=~sum;
return res;
}
void ping(int signo)
{
int len;
int i;
static unsigned short seq=0;
char buff[8192];
struct timeval tv;
struet icmp*icmph=(struct icmp * )buff;
long*data=(long*)icmph→icmp_data;
bzero(buff, 8192);
gettimeofday(&tv, NULL);
icmph→icmp_type=ICMP_ECHO;
icmph→icmp_code=0;
icmph→icmp_cksum=0;
icmph→icmp_id=0;
icmph→icmp_seq=0;
icmph→icmp_id=getpid()&0xffff;
icmph→icmp_seq=seq++;
data[0]=tv.tv_sec;
data[1]=tv.tv_usec;
for(i=8; i< ; i++)
icmph→icmp_data[i]=(unsigned char)i;
icmph→icmp_cksum=in_cksum((unsigned short *)buff, ? 72);
len; sendto(rawsock, buff, 72, 0, &saddr, sizeof(saddr));
alarm(1);
}
void sigint(int signo)
{ printf("CATCH SIGINT !!! \n");
close(rawsock);
exit(0);
}
void dumppkt(char*buf, int len)
{ struct ip*iph=(struct ip*)buf;
int i=iph→ip_h1*4;
struct icmp*icmph=(struct icmp*)&buf[i];
long*data=(long*)iemph→icmp_data;
struct timeval tv;
gettimeofday(&tv, NULL);
if(icmph→icmp_type! =ICMP_ECHOREPLY)
return;
if(icmph→icmp_id! =(getpid()&0xffff))
return;
printf("From %s:ttl=% d seq=% d time=%.2f ms\n",
inet_ntoa(iph→ip_src),iph→ip_ttl?,
icmph→icmp_seq,
(tv.tv_see-data[0])*1000.0+(tv.tv_usec-data[0])/1000.0);
}
int main(int argc, char*argv[])
{ int len;
stuct timeval now;
char recvbuff[8192];
if(1){
printf("%s aaa.bbb.ccc.ddd\n", argv[0]);
exit(1);
}
rawsock=soeket(AF_INET, (2), IPPROTO_ICMP);
if(rawsock<0) {
perror("soeket");
exit(1);
}
bzero ( &saddr, sizeof(saddr));
saddr.sin_family=(3);
if( inet_aton( argv[1], &saddr.sin_addr) <0) {
printf("invalid IP address: %s\n", argv[1]);
exit(1);
}
signal(SICALRM, ping);
signal(SICINT, sigint);
alarm(1);
while (1){
len=read (4), recvbuff, 8192);
if( len<0 && errno=EINTR)
continue;
else it( len<0)
perror("read");
else if( len>0)
dumppkt(recvbuff, len);
}
close (5);
exit(0);
}
第8题
变量7 跳出"; break 1; } } for($j=0;$j<20;$j++){ echo>第二个"; if($j==15){ echo"</20;$j++){>
变量15 跳出"; break 3; } } } echo "nononono"; }
第10题
From: Barbara Smallwood<b_smallwood@echo.net>
Date: Monday, June 10th 20-- 08:42:17 A.M.
Subject: My schedule today
Dave,
I will be out of my office the (144) of the afternoon.
I will be in the south wing at a meeting from 1:30 until 3:00 and then I will be leaving for the day for an eye doctor's appointment. I did not finish double-checking the inventory numbers, but I left them with Margaret and she said she would get them done by 5:00 today. If you need me, do not (145) to call my cell phone: 333-4130.I will be checking e-mail (146) this evening as well.
See you tomorrow,
Barbara
(44)
A.rest
B.rests
C.rested
D.resting
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