以下哪些选项可以得出UserInfo（用户模型）中surname（姓氏）为zhao，qian，sun的查询集（）

Zhao, Qian, Sun and Lee were four shareholders of a limited liability company specialising in bio-technology, each holding 25% of the shares of the company.

Several months later Qian intended to transfer his shares to a listed company for profit and sent notices to the other three shareholders asking for their consent. Zhao agreed and also expressed his willingness to buy Qian’s shares if the price was reasonable. Sun disagreed and claimed his right of priority to buy Qian’s shares. However, Zhao and Sun could not reach an agreement as to the proportion of shares to buy. Lee kept silent upon receipt of the notice.

Since Sun offered a price lower than that of the listed company, Qian entered into a contract to sell his shares to the listed company, which caused a dispute among the four shareholders. Under such circumstances, Lee decided to leave the company and requested the company to purchase his shares.

Required:

In accordance with the relevant provisions of the Company Law:

(a) State how Zhao and Sun’s failure to reach an agreement on the proportion of shares to purchase should be dealt with. (2 marks)

(b) State whether Lee’s request for the company to purchase his shares should be upheld if the dispute was brought to court. (2 marks)

(c) State whether Qian was entitled to transfer his shares to the listed company. (2 marks)

定义结构体数组 struct stu { int num; char name[20]; }x[5]={1,"ZHAO",2,"QIAN",3,"SUN",4,"LEE",5,"ZHOU"}; for(i=1;i＜5;i++) printf("%d%c",x[i].num,x[i].name[2]); 程序执行后的输出结果是( )。

A．2A3N4E5O

B．1H2I3U4E

C．1A2N3E4O

D．1A2N3E4O

]) { struct STU b={"Zhao"，m，85，90)； a[1]=b； } main（） { struct STU c[2]={{"Qian"，f，95，92}，{"Sun"，m 98，99}}； f(c)； printf(”%s，%c，%d，%d，¨，c[o]．name,c[o]．sex，c[o]．score[o]，c[o]．score[1])； printf("%s，%c，%d，%d\n"，c[1]．name，c[1]．sex，c[1]．score[o]，c[1].score [1])； } 程序运行后的输出结果是（）。

A.Zhao，m，85，90，Sun，m，98，99

B.Zhao，m，85，90，Qian，f，95，92

C.Qian，f，95，92，Sun，m，98，99

D.Qian，f，95，92，Zhao，m，85，90

void f(struct STU a [ ]); void f(struct STU a[ ]) { struct STU b=("Zhao",’m’, 85，90); a[1]=b; } void main( ) { struct STU c[2]={{"Qian",’f’, 95, 92},{"Sun",’m’,98, 99}}; f(c); printf("%s,%c,%d,%d,",c[0].name, c[0].sex, c[0].score[0], c[0].score[1]); printf("%s,%c,%d,%d\n", c[1].name, c[1]sex, c[1].score[0], c[1].score[1]); } 程序运行后的输出结果是（ ）。

A、Zhao, m, 85, 90, Sun, m, 98, 99

B、Zhao, m, 85, 90, Qian, f, 95, 92

C、Qian, f, 95, 92, Sun, m, 98, 99

D、Qian, f, 95，92, Zhao, m, 85, 90

One-day Tour of Zhaoqing and Foshan Cities

Depart at 7:30 in the morning, Tour Star Lake and Seven-star Crags(岩). After lunch, go to Foshan and visit the ancient Temple.

One-day Tour of Zhaoqing City

Depart at 8:00 in the morning. Visit Dinghu Mountain and Qingyun Temple. After lunch, do sightseeing(观光) in Star Lake and Seven-star Crags.

One-day Tour of Zhuhai and Zhongshan Cities

Depart at 7:45 in the morning. Visit the former residence of Dr. Sun Yat-sen at Zhongshan, and then go to Zhuhai. After lunch, tour the New Yuan Ming Palace and take a boat around Macao.

One-day Tour of Foshan City

Depart at 8:30 in the morning. Tour the ancient Temple and Ancient Nanfeng Kiln(窑). After lunch, visit Folk Arts Studio and go sightseeing in Liang Garden—one of the most famous four Chinese traditional style. gardens in Guangdong Province.

How many views of natural features will be visited by tourists in Zhaoqing and Foshan Cities?

A．Two.

B．Three.

C．Four.

D．Five.

A．vxdg list

B．ifconfig a

C．lsvg o

D．scstat

A、Furniture

B、Clothes

C、Food

D、Computers