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A.355.B.366.C.365D.445

A.355.

B.366.

C.365

D.445

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更多“A.355.B.366.C.365D.445”相关的问题

第1题

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You
want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?()

A.SELECT last_name, department_name FROM employees NATURAL JOIN departments;

B.SELECT last_name, department_name FROM employees JOIN departments ;

C.SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);

D.SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E.SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);

F.SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

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第2题

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.

You want to retrieve all employees, whether or not they have matching departments in the departments table. Which query would you use?()

A. SELECT last_name, department_name FROM employees NATURAL JOIN departments;

B. SELECT last_name, department_name FROM employees JOIN departments ;

C. SELECT last_name, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id);

D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E. SELECT last_name, department_name FROM employees FULL JOIN departments ON (e.department_id = d.department_id);

F . SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e.department_id = d.department_id)

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第3题

Examine the data in the EMPLOYEES and DEPARTMENTS tables:Also examine the SQL statements t
hat create the EMPLOYEES and DEPARTMENTS tables:On the EMPLOYEES table, EMPLOYEE_ID is the primary key.MGR_ID is the ID of managers and refers to the EMPLOYEE_ID.DEPT_ID is foreign key to DEPARTMENT_ID column of the DEPARTMENTS table.On the DEPARTMENTS table, DEPARTMENT_ID is the primary key.Examine this DELETE statement:What happens when you execute the DELETE statement?()

A. Only the row with department ID 40 is deleted in the DEPARTMENTS table.

B. The statement fails because there are child records in the EMPLOYEES table with department ID 40.

C. The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 110 and 106 are deleted from the EMPLOYEES table.

D. The row with department ID 40 is deleted in the DEPARTMENTS table. Also the rows with employee IDs 106 and 110 and the employees working under employee 110 are deleted from the EMPLOYEES table.

E. The row with department ID 40 is deleted in the DEPARTMENTS table. Also all the rows in the EMPLOYEES table are deleted.

F. The statement fails because there are no columns specifies in the DELETE clause of the DELETE statement.

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第4题

Examine the data in the EMPLOYEES and DEPARTMENTS tables.EMPLOYEESLAST_NAME DEPARTMENT_ID
SALARYGetz 10 3000Davis 20 1500Bill 20 2200Davis 30 5000Kochhar 5000DEPARTMENTSDEPARTMENT_ID DEPARTMENT_NAME10 Sales20 Marketing30 Accounts40 AdministrationYou want to retrieve all employees, whether or not they have matching departments in the departments table.Which query would you use?()

A. SELECT last_name, department_name FROM employees , departments();

B. SELECT last_name, department_name FROM employees JOIN departments();

C. SELECT last_name, department_name ON (e. department_ id = d. departments_id); FROM employees() e JOIN departments d

D. SELECT last_name, department_name FROM employees e RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E. SELECT last_name, department_name FROM employees() , departments ON (e. department _ id = d. department _id);

F. SELECT last_name, department_name FROM employees e LEFT OUTER JOIN departments d ON (e. department _ id = d. department _id);

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第5题

Examine the structure of the EMPLOYEES and DEPARTMENTS tables: EMPLOYEESColumn name Data t
ype RemarksEMPLOYEE_ID NUMBER NOT NULL, Primary KeyEMP_NAME VARCHAR2 (30)JOB_ID VARCHAR2 (20)SALARY NUMBERMGR_ID NUMBER References EMPLOYEE_ID COLUMNDEPARTMENT ID NUMBER Foreign key to DEPARTMENT ID column of the DEPARTMENTS tableDEPARTMENTSColumn name Data type RemarksDEPARTMENT_ID NUMBER NOT NULL, Primary Key DEPARTMENT_NAME VARCHAR2(30)MGR_ID NUMBER References MGR_ID column of the EMPLOYEES tableEvaluate this SQL statement:SELECT employee_id, e.department_id, department_name, salaryFROM employees e, departments dWHERE e. department_id = d.department_id;Which SQL statement is equivalent to the above SQL statement? ()

A. SELECT employee_id, department_id, department_name, salary FROM employees WHERE department_id IN (SELECT department_id FROM departments);

B. SELECT employee_id, department_id, department_name, salary FROM employees NATURAL JOIN departments;

C. SELECT employee_id, d.department_id, department_name, salary FROM employees e JOIN departments d ON e.department _ id = d. department_id;

D. SELECT employee_id, department_id, department_name, Salary FROM employees JOIN departments USING (e.department_id, d.department_id);

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第6题

Click the Exhibit button and examine the data in the EMPLOYEES and DEPARTMENTS tables.You
want to retrieve all employees‘ last names, along with their managers‘ last names and their department names. Which query would you use?()

A.SELECT last_name, manager_id, department_name FROM employees e FULL OUTER JOIN departments d ON (e.department_id = d.department_id);

B.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on (e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

C.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on (e.manager_id = m.employee_id) LEFT OUTER JOIN departments d ON (e.department_id = d.department_id);

D.SELECT e.last_name, m.last_name, department_name FROM employees e LEFT OUTER JOIN employees m on (e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

E.SELECT e.last_name, m.last_name, department_name FROM employees e RIGHT OUTER JOIN employees m on (e.manager_id = m.employee_id) RIGHT OUTER JOIN departments d ON (e.department_id = d.department_id);

F.SELECT last_name, manager_id, department_name FROM employees e JOIN departments d ON (e.department_id = d.department_id) ;

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第7题

A.

B.

C.

D.

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第8题

A.

B.

C.

D.

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第9题

Examine the structure of the EMPLOYEES and DEPARTMENTS tables:EMPLOYEESEMPLOYEE_ID NUMBERD
EPARTMENT_ID NUMBERMANAGER_ID NUMBERLAST_NAME VARCHAR2(25)DEPARTMENTSDEPARTMENT_ID NUMBERMANAGER_ID NUMBERDEPARTMENT_NAME VARCHAR2(35)LOCATION_ID NUMBERYou want to create a report displaying employee last names, department names, and locations. Which query should you use?()

A.SELECT e.last_name, d. department_name, d.location_id FROM employees e NATURAL JOIN departments D USING department_id ;

B.SELECT last_name, department_name, location_id FROM employees NATURAL JOIN departments WHERE e.department_id =d.department_id;

C.SELECT e.last_name, d.department_name, d.location_id FROM employees e NATURAL JOIN departments d;

D.SELECT e.last_name, d.department_name, d.location_id FROM employees e JOIN departments d USING (department_id );

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