A.float [][] a = new float[4][5];
B.float [][] a = new float[5][4];
C.int [][] a = new int[4][5];
D.int [][] a = new int[5][4];
E.int a [][] ={{0,1,9,2}, {8,3,0,4}, {0,6,0,7,}, {4,6,1,7,}, {3,1,9,4}};
第2题
A.p[0][3]
B.p[1][2]
C.p[0][2]
D.p[1][3]
第3题
A.Dim a(4) As Integer
B.Option Base 1:Dim a(5)
C.Dim a &(5)
D.Dime a(5) As Integer
第4题
A.Dim a(4)As Integer
B. Option Base 1:Dim a(5)
C.Dim a&(5)
D.Dime a(5)As Integer
第5题
A.Dim a(4) As Integer
B.Option Base 1:Dim a(5)
C.Dim a & (5)
D.Dime a(5) As Integer
第6题
A.Dim a(4)As Integer
B.Option Base 1:Dim a(5)
C.Dim a &(5)
D.Dime a(5)As Integer
第9题
A.scanf("%lf%lf%lf%lf%lf,a) ;
B.for(i=0;i<=5;i++)scanf("%lf,a+i);
C.while(i<5)scanf("%lf",&a[i++]);
D.while(i<5)seanf("%lf,a+i);
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